Average & Mean MCQs with Answers — 148 Solved from Past Papers
148 solved Average & Mean MCQs collected from real PPSC, FPSC, SPSC, KPPSC, BPSC & NTS past papers (2002–2025). Tap an option to attempt — see correct answer instantly. Download the full PDF for offline revision.
The average monthly income of A&B is 50,500. The average monthly income of B&C is 62,500 and the average monthly income of A&C is 52,000. What is monthly income of A?
Show solution
(A+B)+(A+C)-(B+C) = 2A. So 2A = 50500×2 + 52000×2 – 62500×2 = 101000+104000-125000 = 80000. A = 40,000.
The average monthly income of A&B is 50,500 The average monthly income of B&C is 62,500 and the average monthly income of A&C is 52,000. What is monthly income of A?
Show solution
Same as Q1: 2A = 2(50500)+2(52000)-2(62500) = 80000, so A = 40,000.
Three years ago, the average age of a family of 5 members was 17 years. A baby having been born and the average age of the family is the same as three years ago. The present age of the baby (in years) is?
Show solution
3 yrs ago sum of 5 ages = 5×17 = 85. Now sum = 85+15 = 100. With baby added (6 members) avg still 17 so sum = 102. Baby = 102-100 = 2 years.
Roshan bought 5 pants at Rs25 each, 10 shirts at Rs5O each and 15 ties at Rs35 each. Find the average price of all the articles?
Show solution
Total cost = 5×25 + 10×50 + 15×35 = 125+500+525 = 1150. Items = 30. Avg = 1150÷30 = 38.33.
The average of the first 100 natural number is?
Show solution
Average of first n natural numbers = (n+1)÷2. For n=100: 101÷2 = 50.5.
The average weight of 7 people is 70 kg. If one person weighing 80 kg is replaced by a person weighing 60 kg, what will be the new average weight?
Show solution
Original total = 7×70 = 490. Replace 80 by 60 → new total = 470. New avg = 470÷7 = 67.14.
The distance between two cities is 203 miles, and the journey takes 3 1/2 hours. What is the average speed of the vehicle?
Show solution
Speed = distance ÷ time = 203 ÷ 3.5 = 58 mph.
Acar travels a distance of 510 km in 6 hours. What is the average speed of the car?
Show solution
Average speed = 510 ÷ 6 = 85 km/h.
Ifthe mean of 7 terms is 40, the sum of those terms will be?
Show solution
Sum = mean × count = 40 × 7 = 280.
Atherapist is preparing a poster that will clarify some of the data in an in service presentation. The poster reflects the mode, median, and mean of a set of data. The data consist of the numbers 2, 2, 4, 9, and 13. If presented in the above order (mode, median mean), which of the following is the correct list of answers calculated from the data?
Show solution
Data 2,2,4,9,13. Mode = 2 (most frequent). Median = middle = 4. Mean = 30÷5 = 6. Order mode,median,mean = 2,4,6.
The average of 5 numbers is 42, if we include sixth number 48, then the new average will be?
Show solution
Sum of 5 = 5×42 = 210. Add 48 → sum = 258. New avg = 258÷6 = 43.
The average height of a class of 25 students is 4.4 feet. A student of height 5.7 feet is newly enrolled. Find the new average?
Show solution
Total height of 25 = 25×4.4 = 110. Add 5.7 → 115.7. New avg = 115.7÷26 = 4.45 feet.
Aman covers half of his journey at 6 km/h and the remaining half at 3 km/h. His average speed is?
Show solution
Equal half distances → use harmonic mean: 2×6×3÷(6+3) = 36÷9 = 4 km/h.
The average age of 11 players of a cricket team is decreased by 2 months when two of them aged 17 years and 20 years are replaced by two new players. The average age of the new players is?
Show solution
Avg drops 2 months × 11 players = 22 months total drop. Removed ages = 17y + 20y = 37y = 444 months. New pair sum = 444-22 = 422 months. Avg of new = 211 months = 17 years 7 months.
The average of x, X2, X3 and Xq is 16. Half the sum of x2, x3, X4 is 23. What is the value of x?
Show solution
Sum of x,x2,x3,x4 = 4×16 = 64. Sum x2+x3+x4 = 2×23 = 46. So x = 64-46 = 18.
The sum of five numbers is 555. The average of first two numbers is 75 and the third number is 115. What is the average of the last two numbers?
Show solution
Sum of first two = 2×75 = 150. Third = 115. Last two sum = 555-150-115 = 290. Avg = 290÷2 = 145.
The mean proportional between 64 and 81 is?
Show solution
Mean proportional of 64 and 81 = √(64×81) = 8×9 = 72.
The mean of five numbers is 18. If one number is excluded, their mean is 16. The excluded number is?
Show solution
Sum of 5 = 5×18 = 90. Sum of 4 = 4×16 = 64. Excluded = 90-64 = 26.
The mean of 100 items was found to be 30. If at the time of calculation two items were wrongly taken as 32 and 12 instead of 23 and 11, find the correct mean?
Show solution
Original sum = 100×30 = 3000. Correction: (23+11) – (32+12) = -10. Corrected sum = 2990. New mean = 29.9.
The average height of five pupils is 68 inches. If one 70 inches and other three are 76 inches, then what is the height (in inches) of the fifth pupil?
Show solution
Total = 5×68 = 340. Known: 70 + 3×76 = 70+228 = 298. Fifth = 340-298 = 42 inches.
Acar travels 100 km at a speed of 60 km/h and returns with a speed of 40 km/h. Calculate the average speed for the whole journey?
Show solution
Equal distances → harmonic mean = 2×60×40÷(60+40) = 4800÷100 = 48 km/h.
The diameter of a wheel of a car is 48 cm. If the car travels at an average speed of 3.5 km/h. The number of revolutions made by the wheel per minute is?
Show solution
Distance per min = 3500÷60 m = 58.33 m = 5833.33 cm. Circumference = π×48 = 150.80 cm. Revs/min = 5833.33÷150.80 = 38.68.
The arithmetic mean is 25 and all the sum of observations is 350, then the number of observations is?
Show solution
n = sum ÷ mean = 350 ÷ 25 = 14.
The number of observations is 30 and the value of arithmetic mean is 15, then sum of all values is?
Show solution
Sum = mean × n = 15 × 30 = 450.
Ali obtained an average marks of 48 in Physics, Chemistry and Biology. What are total marks of three subjects?
Show solution
Total marks = 48 × 3 = 144.
Shahzad family has an average age of 72 years. If the family has total 4 members, what is their collective age?
Show solution
Total = 72 × 4 = 288 years.
The average of three numbers is 54. If two numbers are 48 and 58, what is the third number?
Show solution
Sum of 3 = 3×54 = 162. Third = 162-48-58 = 56.
Oncalculation means (average) of 15 numbers was 64. One of the number 24 was misread as 34. What is the correct mean?
Show solution
Original sum = 15×64 = 960. Correct sum = 960-34+24 = 950. Mean = 950÷15 = 63.33 = 63 1/3.
The ages of six girls are 120 months, 124 months, 123 months, 130 months, 130 months, and 129 months, find their average age?
Show solution
Sum = 120+124+123+130+130+129 = 756. Avg = 756÷6 = 126 months.
Average of 10 values is 200. Sum of nine of them is 1850. Find 10th value?
Show solution
Total of 10 = 200×10 = 2000. 10th = 2000-1850 = 150.
The mean proportional of 0.25 and 0.04 is?
Show solution
Mean proportional = √(0.25×0.04) = √0.01 = 0.1.
The average of 7 consecutive numbers is 20. The largest of these numbers is?
Show solution
Middle of 7 consecutive = avg = 20. Numbers: 17..23. Largest = 23.
Calculate the average of 1, 2,3, 4,5?
Show solution
Avg = (1+2+3+4+5)÷5 = 15÷5 = 3.
A boat travels with a speed of 100 km/h when going from initial point to destination. While the speed of the boat was 130 km/h when coming back from destination to initial point. What was the average speed in whole journey?
Show solution
Harmonic mean = 2×100×130÷(100+130) = 26000÷230 = 113.04 ≈ 113 km/h.
The average salary of all the workers in a restaurant is Rs. 8000. The average salary of 7 cooks is Rs. 12000 and the average salary of the rest is Rs. 6000. How many workers are there working in that restaurant?
Show solution
Let n = total. 7×12000 + (n-7)×6000 = 8000n. 84000+6000n-42000 = 8000n → 42000 = 2000n → n = 21.
A biker went to Lahore at an average of 70 km/h while reached back home at an average speed of 60 km/h. What is the entire journey’s average speed?
Show solution
Harmonic mean = 2×70×60÷(70+60) = 8400÷130 = 64.62 km/h.
Average of five numbers is 4. If a number 2 is added in all the five numbers, what will be the average?
Show solution
Adding constant k to every value shifts mean by k. New avg = 4+2 = 6.
What is the average of first 150 natural numbers?
Show solution
Avg of first n naturals = (n+1)÷2. For n=150: 151÷2 = 75.5.
lf sum of all 10 values in the data set are 10, then what will be average?
Show solution
Average = sum ÷ n = 10 ÷ 10 = 1.
The mean of 5 observations is 10. A new observation 10 is added, then mean of 6 observations is?
Show solution
Sum of 5 = 50. Add 10 → 60. Mean = 60÷6 = 10.
The average income of A and B is 50000 and average income of B and C is 60000 and Average income of A and Cis 55000. What is the income of B?
Show solution
(A+B)+(B+C)+(A+C) = 2(A+B+C). Sum of pair-totals = 100000+120000+110000 = 330000. A+B+C = 165000. B = 165000-(A+C) = 165000-110000 = 55000.
The mean weight of 100 students ina class is 46 kg. Then mean weight of boys is 50 kg and that of girls is 40 kg. Therefore, the number of boys is?
Show solution
Let boys=b, girls=100-b. 50b+40(100-b) = 100×46 = 4600 → 10b = 600 → b = 60.
The average of the first five multiples of 9 is?
Show solution
First 5 multiples of 9: 9,18,27,36,45. Sum = 135. Avg = 27.
The average of 6 numbers is 30. If the average of the first four is 25 and that of the last three is 35, the fourth number is?
Show solution
Total = 180. First 4 sum = 100. Last 3 sum = 105. 4th = 100+105-180 = 25 (4th counted in both groups).
Ifx?—y?=28 andx—y=8, then the average of x and y is?
Show solution
x²-y² = (x+y)(x-y) = 28; with x-y = 8, x+y = 28÷8 = 3.5. Avg = 3.5÷2 = 1.75.
The average of 50 numbers is 30; remove 35 and 25, new average?
Show solution
Original total = 50×30 = 1500. Remove 35+25 = 60 → new total = 1440 for 48 nums. Avg = 1440÷48 = 30.
Average of 10 innings is 32; runs in next innings to raise average by 4?
Show solution
Sum of 10 = 320. New avg = 36 → sum of 11 = 396. Next innings = 396-320 = 76.
The average age of 3 friends is 23. Even if the age of 4th friend is added the average becomes 23. What is the age of 4th friend?
Show solution
Sum of 3 = 69. Sum of 4 = 4×23 = 92. 4th = 92-69 = 23.
The mean proportional between 2 and 8 is?
Show solution
Mean proportional = √(2×8) = √16 = 4.
The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is?
Show solution
Sum of 5 = 135. Sum of 4 = 100. Excluded = 35.
There are two sections A and B of a class, consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class?
Show solution
Weighted avg = (36×40 + 44×35)÷80 = (1440+1540)÷80 = 2980÷80 = 37.25 kg.
Aclass had 14 boys with an average height of 5.3 feet. A new boy joined the class. Now the average of 15 boys in the class was 5.25 feet. Find the height of the new boy?
Show solution
Total of 14 = 74.2. Total of 15 = 78.75. New boy = 78.75-74.2 = 4.55 feet.
The average (arithmetic mean) of 5, 10, 15 and x is 20. What is the value of x?
Show solution
Sum = 4×20 = 80. So 5+10+15+x = 80, x = 50.
The mean of 5 observations is 60, the mean of 10 observations is 30 and mean of 15 observations is 20. The mean of all 30 observations is?
Show solution
Combined mean weighted: (5×60+10×30+15×20)÷30 = (300+300+300)÷30 = 30.
Average age of A and B is 30 years, that of B and Cis 32 years and the average PREPARATION WIT age of C and A is 34 years. The age of C is?
Show solution
(A+B)+(B+C)+(C+A) = 2(A+B+C) = 2(30+32+34) = 192. So A+B+C = 96. C = 96-(A+B) = 96-60 = 36.
The mean proportional of 4 and 16 is?
Show solution
Mean proportional = √(4×16) = √64 = 8.
When a student weighting 45 kgs left a class the average weight of the remaining 59 student icreased by 200g . What is average weight of the remaining 59 students?
Show solution
Let original avg of 60 = X. Then 60X-45 = 59(X+0.2) → X = 56.8. New avg = 56.8+0.2 = 57.
If the average of five numbers is 6.92, then the sum of numbers is?
Show solution
Sum = 5×6.92 = 34.6.
Four years ago the average age of A,B and C was 25 years. Five years ago the average of B and C was 20 years. As present is of A?
Show solution
4 yrs ago A+B+C = 75; now = 75+12 = 87. 5 yrs ago B+C = 40; now = 40+10 = 50. A = 87-50 = 37.
If average of 7 numbers is 40, What was the sum of the numbers?
Show solution
Sum = 7×40 = 280.
Find the average of the 277, 278, 279, 280, 281, 282, 283?
Show solution
Middle of 7 consecutive = 280. Sum = 7×280 = 1960; avg = 280.
Five years ago the average of AandB was 15 years. Average age of A, Band C today is 20 years how old will C be after 10 years?
Show solution
5 yrs ago A+B = 30; now = 40. Now A+B+C = 60. C now = 20. After 10 yrs: 30.
If 3x+3y=7 and 8x + 7y = 12, what is average of x and y?
Show solution
3x+3y=7 → x+y = 7/3. (We don't need individual x,y.) Avg = (x+y)÷2 = 7/6.
The speed of the bus going from Islamabad to Murree was 100 km/h, while the speed of the bus was 130 km/h when coming back from Murree to Islamabad. What was the average speed in whole journey?
Show solution
Harmonic mean = 2×100×130÷(100+130) = 26000÷230 = 113.04 km/h.
The average age of A, B, C, Dand E is 40 years. The average age of A and B is 35 years and the average of C and Dis 42 years. Age of E is?
Show solution
Total of 5 = 200. A+B = 70. C+D = 84. E = 200-70-84 = 46.
What is the average of first 100 natural numbers?
Show solution
Avg first 100 naturals = 101÷2 = 50.5.
The average of five consecutive even numbers starting with 4, is?
Show solution
Numbers: 4,6,8,10,12. Sum = 40. Avg = 8.
What is the average of even numbers from 1 to 81?
Show solution
Even nums 2..80: count = 40. Avg = (2+80)÷2 = 41.
The speed of the train going from Nagpur to Allahabad is 100 km/h while when coming back from Allahabad to Nagpur, its speed is 150 km/h. Find the average speed during the whole journey?
Show solution
Harmonic mean = 2×100×150÷(100+150) = 30000÷250 = 120 km/h.
Five years ago, the average age of A, B, C, and D was 45 years. With E joining them now, the average of all five is 49 years. How old is E?
Show solution
5 yrs ago A+B+C+D sum = 180; now = 180+20 = 200. With E sum = 5×49 = 245. E = 245-200 = 45.
The is equal to the sum of all the values in the data divided by the number of values in the data?
Show solution
Definition: 'Mean' = sum of values divided by number of values.
lf the average arithmetic means of 8, 12, 15, 21, x and 11 is 17 then what is x?
Show solution
Sum of 6 = 6×17 = 102. Known sum 8+12+15+21+11 = 67. x = 102-67 = 35.
If Mary traveled 116 miles on day 1, 130 miles on day 2, 114 miles on day 3. How many miles per day did she average?
Show solution
Average = (116+130+114)÷3 = 360÷3 = 120 miles/day.
Find the average of 8 13 25 43 and 11?
Show solution
Sum = 8+13+25+43+11 = 100. Avg = 100÷5 = 20.
The average of 5 quantities is 6. The average of 3 of them is 4. What is the average of remaining 2 numbers?
Show solution
Sum of 5 = 30. Sum of 3 = 12. Remaining 2 sum = 18, avg = 9.
The arithmetic mean between 4 and 6 is?
Show solution
Arithmetic mean of 4 and 6 = (4+6)÷2 = 5. (Option 'S' is OCR for 5.)
Ifthe average of 5, 6, 7 and X is 10. What is the value of 'X'?
Show solution
Sum = 4×10 = 40. X = 40-(5+6+7) = 22.
Find the average of all numbers between 6 and 34 which are divisible by 5?
Show solution
Multiples of 5 between 6 and 34: 10,15,20,25,30. Sum = 100. Avg = 20.
Reeya obtained 65, 67, 78, 82 and 85 out of 100 in different subjects, what will be the average?
Show solution
Sum = 65+67+78+82+85 = 377. Avg = 377÷5 = 75.4.
Find out the average of A and B if the given value of 16 A + 16 B = 48?
Show solution
16A+16B = 48 → A+B = 3. Avg = 1.5.
Find the average of 8, 13, 25, 43, and 11?
Show solution
Sum = 8+13+25+43+11 = 100. Avg = 20.
The average of four consecutive odd numbers is 24. Find the largest number?
Show solution
4 consecutive odd with avg 24: 21,23,25,27. Largest = 27.
What is the average of 1/2, 5/6, 3/4, 5/12?
Show solution
LCM denom 12: 6/12+10/12+9/12+5/12 = 30/12. Avg = (30/12)÷4 = 30/48 = 5/8.
The average weight of A, B and Cis 45 Kg. If the average weight of A and B is 40 Kg and that of B and Cis 43 Kg, then weight of B is?
Show solution
A+B+C = 3×45 = 135. A+B = 80. B+C = 86. B = 80+86-135 = 31.
Find the average of all prime numbers between 30 and 50?
Show solution
Primes between 30 and 50: 31,37,41,43,47. Sum = 199. Avg = 39.8.
Find the average of first 40 natural numbers?
Show solution
Avg first n naturals = (n+1)÷2. For n=40: 41÷2 = 20.5.
The average of 17 results is 60. If the average of first 9 results is 57 and that of the last 9 results is 65, then what will be the value of 9th result?
Show solution
Sum of 17 = 1020. First 9 sum = 513. Last 9 sum = 585. 9th counted twice: 513+585-1020 = 78.
Three years ago the average age of A and B was 18 years. With C joining them, the average age becomes 22 years. How old is C now?
Show solution
3 yrs ago A+B = 36; now = 42. A+B+C = 3×22 = 66. C = 66-42 = 24.
Find the average of first 97 natural numbers?
Show solution
Avg of first n naturals = (n+1)÷2. For n=97: 98÷2 = 49.
The average of three numbers is 77. The first number is twice the second and the second number is twice the third. Find the first number?
Show solution
Let third = x, second = 2x, first = 4x. Sum 7x = 3×77 = 231 → x = 33. First = 4×33 = 132.
Find the average of all the numbers between 11 and 36 which are divisible by 5?
Show solution
Multiples of 5 between 11 and 36: 15,20,25,30,35. Sum = 125. Avg = 25.
The average weight of X, Y and Z is 45 kg. If the average weight of X and Y be 40 kg and that of Y and Z be 43 kg, then the weight of Y is?
Show solution
X+Y+Z = 135. X+Y = 80. Y+Z = 86. Y = 80+86-135 = 31.
The average marks of four subjects is 120. If 33 was misread as 13 during the calculation, what will be the correct average?
Show solution
Original sum = 4×120 = 480. Correction adds (33-13) = 20. Correct sum = 500. Avg = 125.
If 16a+16b = 48, what is the average of aand b?
Show solution
16(a+b) = 48 → a+b = 3. Avg = 1.5.
Atrain moves with a speed of 30 km/hr for 12 minutes and for next 8 minutes at a speed of 45 km/hr the average speed of the train is?
Show solution
Dist = 30×(12/60)+45×(8/60) = 6+6 = 12 km. Time = 20/60 = 1/3 hr. Avg speed = 12÷(1/3) = 36 km/h.
Average of four numbers is 24. What is the sum of the four numbers?
Show solution
Sum = 4×24 = 96.
Ifthe sum of three numbers is 93, then the average of the numbers is?
Show solution
Avg = 93÷3 = 31.
The average of the numbers 0.1, 0.21, 0.31, 0.41, 0.51 is?
Show solution
Sum = 0.1+0.21+0.31+0.41+0.51 = 1.54. Avg = 1.54÷5 = 0.308.
Acar travels a distance of 75 km at the speed of 25 km/hr. It covers the next 25 km of its journey at the speed of 5 km/hr and the last 50 km of its journey PREPARATION WI at the speed of 25 km/hr. What is the average speed of the car?
Show solution
Times: 75/25 + 25/5 + 50/25 = 3+5+2 = 10 hr. Total dist = 150 km. Avg speed = 150÷10 = 15 km/h.
The average speed of a bus is three- fifth of the average speed of a car which covers 3250 km in 65 hours. What is the average speed of the bus?
Show solution
Car speed = 3250÷65 = 50 km/h. Bus = 3/5 × 50 = 30 km/h.
Acar left Lahore at 7.12 am and arrived in Multan, 180 miles distant at 10.57 am. What was its average speed in miles per hour?
Show solution
Time = 10:57 – 7:12 = 3 hr 45 min = 3.75 hr. Speed = 180÷3.75 = 48 mph.
Alibrary received an average of 510 visitors every Sunday and on other days 240. What is average number of visitors in a month of 30 days beginning with Sunday?
Show solution
30-day month starting Sunday has 5 Sundays + 25 other days. Total visitors = 5×510+25×240 = 2550+6000 = 8550. Avg = 8550÷30 = 285.
The average age of A, Band Cis 45. Furthermore average age of A and Bis 40 and of B and Cis 43. Find the age of B?
Show solution
A+B+C = 135. A+B = 80. B+C = 86. B = 80+86-135 = 31.
Find the average of 5/6, 4/3, 3/4?
Show solution
LCM 12: 10/12+16/12+9/12 = 35/12. Avg = (35/12)÷3 = 35/36.
Average monthly income of P and Qis Rs. 5050. The average monthly income of Qand R is Rs. 6250. The average monthly income of P and R is Rs. 5200. What will be the monthly income of Q?
Show solution
P+Q = 10100, Q+R = 12500, P+R = 10400. Sum = 33000 = 2(P+Q+R) → P+Q+R = 16500. Q = 16500-10400 = 6100.
Rashid buys 3 books for Rs. 16 each and four books for Rs. 23 each. What will be the average price of the books?
Show solution
Total cost = 3×16+4×23 = 48+92 = 140. Avg = 140÷7 = 20.
lf the arithmetic mean of 10, 12, 15, x and 20 is 14, then the value of x is?
Show solution
Sum = 5×14 = 70. Known sum 10+12+15+20 = 57. x = 70-57 = 13.
The arithmetic mean of 6 numbers is 10. If each number is multiplied by 3, then the new arithmetic mean is?
Show solution
Multiplying every value by k multiplies mean by k. New mean = 10×3 = 30.
What is the Arithmetic Mean of the numbers 10, 20, 30, 40, and 50?
Show solution
Sum = 10+20+30+40+50 = 150. Avg = 150÷5 = 30.
If three arithmetic means are inserted between 5 and 25, the second arithmetic mean is?
Show solution
Common difference d = (25-5)÷4 = 5. AMs are 10,15,20. Second = 15.
The mean of 14 numbers is 6. What will be the new mean if 3 is added to every number?
Show solution
Adding k to every value shifts mean by k. New mean = 6+3 = 9.
Ifthe mean of 9, 8, 10, x, 12 is 15, find the value of x?
Show solution
Sum = 5×15 = 75. Known 9+8+10+12 = 39. x = 75-39 = 36.
The arithmetic mean of the first 10 prime numbers is?
Show solution
First 10 primes: 2,3,5,7,11,13,17,19,23,29. Sum = 129. Avg = 12.9.
What is the 3rd arithmetic mean out of 4 arithmetic means inserted between 18 and 3?
Show solution
d = (3-18)÷5 = -3. Means: 15,12,9,6. 3rd = 9.
A person travels from A to B at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for both the trips?
Show solution
Return speed = 1.5×40 = 60. Harmonic mean = 2×40×60÷100 = 48 km/h.
What is the arithmetic mean of 34, 44, 56, and 78?
Show solution
Sum = 34+44+56+78 = 212. Avg = 212÷4 = 53.
The speed of car is 30 km in the first hour and 32 km in the second hour. Its average speed is?
Show solution
Total = 30+32 = 62 km in 2 hr. Avg = 31 km/h.
Average of first 10 multiples of 7 is?
Show solution
First 10 multiples of 7: 7,14,…,70. Avg = (7+70)÷2 = 38.5.
The average of six numbers is X and the average of three of these is Y. If the average of the remaining three is Z, then?
Show solution
6X = sum of all 6 = (3Y)+(3Z) → 6X = 3Y+3Z → 2X = Y+Z.
If x+y=6, y+z=7 z+x=9 the average (arithmetic) of x, y and z is?
Show solution
Sum of equations: 2(x+y+z) = 6+7+9 = 22 → x+y+z = 11. Avg = 11÷3.
Ifx+y=6,y+z=7andz+x=9, the average (arithmetic mean) of x, y and z is?
Show solution
Sum of equations: 2(x+y+z) = 22 → x+y+z = 11. Avg = 11/3.
Ifx?-y?=28 and x -y =8, what is the average of x and y?
Show solution
(x+y)(x-y) = 28; x-y = 8 → x+y = 3.5. Avg = 1.75.
Ifthe arithmetic mean of 6, 8, 10, x, 7 is 8 the value of x will be?
Show solution
Sum = 5×8 = 40. x = 40-(6+8+10+7) = 9.
The average (arithmetic mean) of 5, 10, 15, and zis 20. What is z?
Show solution
Sum = 4×20 = 80. z = 80-(5+10+15) = 50.
The speed of the train going from Nagpur to Allahabad is 100 km/h while coming back from Allahabad to Nagpur, its speed is 150 km/h. Find the average speed during the whole journey?
Show solution
Harmonic mean = 2×100×150÷250 = 120 km/h.
The average of first five multiples of 3 is?
Show solution
First 5 multiples of 3: 3,6,9,12,15. Sum = 45. Avg = 9.
The average age of a group of 13 boys is 13. When two more boys join the group, the average rose by 2 years. The sum of the ages of the two new boys is?
Show solution
Sum of 13 = 169. New sum of 15 with avg 15 = 225. Two new boys sum = 225-169 = 56.
What is the arithmetic mean (average) of 2,4, 6, 8,10 and 12?
Show solution
Sum = 2+4+6+8+10+12 = 42. Avg = 42÷6 = 7.
What is the average (arithmetic mean) of the positive integers from 1 to 100 inclusive?
Show solution
Avg first 100 naturals = (1+100)÷2 = 50.5.
If the average (arithmetic mean) of 5, 6, 7 and wis 8, what is the value of w?
Show solution
Sum = 4×8 = 32. w = 32-(5+6+7) = 14.
Onacertain project the only grades awarded were 75 and 100. If 85 students completed the project and the average of their grades was 85, how many earned 100?
Show solution
Let x earn 100. 100x+75(85-x) = 85×85 = 7225 → 25x = 850 → x = 34.
The average of three numbers is 20. If two numbers are 16 and 22, the third is?
Show solution
Sum of 3 = 3×20 = 60. Third = 60-(16+22) = 22.
There are four numbers. Average of the first three is 20 and that of the last three is 19. If the last number is 22, find the first number?
Show solution
Let nums be a,b,c,d. a+b+c = 60, b+c+d = 57, d = 22 → b+c = 35. a = 60-35 = 25.
Find the average of 49, 51, 29?
Show solution
Sum = 49+51+29 = 129. Avg = 129÷3 = 43.
The average of 13 results is 68 The average of first seven is 63 and that of the last seven is 70 the seventh result is?
Show solution
Sum of 13 = 884. First 7 = 441; last 7 = 490. 7th counted twice: 441+490-884 = 47.
The speed of a car is 30km first hour and 32 km in the second hour. Its average speed is?
Show solution
Total dist = 62 km in 2 hr. Avg = 31 km/h.
A batsman has a certain average of runs for 16 innings. In the 17th innings, he makes a score of 85 runs, thereby increasing his average by 3. What is the average after the 17th innings?
Show solution
Let avg of 16 = X. Then 16X+85 = 17(X+3) = 17X+51 → X = 34. New avg = 37.
Mary jogs 9 km at a speed of 6 km per hour. At what speed would she need to jog during the next 1.5 hours to have an average of 9 km per hour for the entire jogging session?
Show solution
9 km at 6 km/h = 1.5 hr. Total time = 1.5+1.5 = 3 hr. Target total dist = 9×3 = 27 km. Next dist = 18 km in 1.5 hr → 12 km/h.
If p?—q?=48 and p—q = 12, what is the average of p and q?
Show solution
(p+q)(p-q) = 48; p-q = 12 → p+q = 4. Avg = 2.
There are four numbers. Average of the first three is 15 and that of the last three is 16. If the last number is 19 find the first number?
Show solution
a+b+c = 45, b+c+d = 48, d = 19 → b+c = 29. a = 45-29 = 16.
The speed of a car is 30 km first hour and 32 km in the second hour. Its average speed is?
Show solution
Total = 30+32 = 62 km in 2 hr. Avg = 31 km/h.
Acar covers 160 km distance in 4 hours. Find the average speed of car?
Show solution
Avg speed = 160÷4 = 40 km/h.
The average of 5 numbers is 34. If there are 28, 30, 32, then find the average of rest of them²
Show solution
Sum of 5 = 5×34 = 170. Known 28+30+32 = 90. Rest 2 sum = 80, avg = 40.
Astudent of physics obtains the average of 60 in his 4 physics tests. How many marks in his fifth test will bring the average to 65?
Show solution
Sum of 4 tests = 240. New sum for avg 65 over 5 = 325. 5th test = 85.
The captain of a cricket team 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team²
Show solution
Captain = 26, wicketkeeper = 29. Let team avg = T. 11T-26-29 = 9(T-1) → 11T-55 = 9T-9 → 2T = 46 → T = 23.
Find the average age of a family of five members, whose ages are 42, 49, 56, 63 and 35 years respectively?
Show solution
Sum = 42+49+56+63+35 = 245. Avg = 245÷5 = 49.
Mean of 10, 30, Y, and 50 is 50. Y is?
Show solution
Sum = 10+30+Y+50 = 4×50 = 200 → Y = 110.
Inthe morning Sarah read 100 pages at the rate of 60 pages per hour. In the evening, she read another 100 pages at the rate of 40 pages per hour. What was the average rate of reading for the day?
Show solution
Morning time = 100/60 = 5/3 hr; evening = 100/40 = 5/2 hr. Total pages = 200, total time = 25/6 hr. Rate = 200÷(25/6) = 48 pages/hr.
Average & Mean MCQs for PPSC, FPSC, NTS & All Pakistani Competitive Exams
Average & Mean is one of the most predictable topics in Pakistani competitive exam Math. From PPSC Lecturer, Sub-Inspector and Tehsildar tests to FPSC CSS Screening (MPT), NTS NAT/GAT, OTS, CTS, KPPSC, SPSC, BPSC and AJKPSC — almost every paper contains 1 to 5 average-based questions. Mastering this one topic alone can secure 3–5 marks in any One Paper format exam because the formulas are short and the question patterns repeat verbatim across years.
QuizWing has compiled 148 verified average & mean MCQs from real past papers spanning 2002–2025 — every question cross-checked against official answer keys. The bank covers arithmetic mean, weighted average, combined average, age-average word problems, and average-of-numbers shortcuts.
What types of average questions appear?
- Simple arithmetic mean — “Average of 12, 18, 24, 30 and 36 is?”
- Combined average — “Average income of A & B is 50,500; B & C is 62,500; find A’s income”
- Average with new member added/removed — “Average age of 5 family members was 17 years; baby born — find baby’s age”
- Weighted average — different weights for different groups (boys/girls, classes, factories)
- Average of consecutive integers — middle term equals the average
- Average speed problems — total distance ÷ total time (not arithmetic mean of two speeds)
Key average & mean formulas
Mental-math shortcuts
- Consecutive integers — average = (first + last) ÷ 2 (e.g. 1 to 10 → average = 5.5)
- Equally-spaced series — same shortcut works for any arithmetic progression
- Shift-from-anchor trick — pick a round number close to all values, average the differences, add back to the anchor
- Member added/removed — change in average × new count = the value of the added/removed member ± (old average × delta)
- Two equal distances at different speeds — never use (x + y) ÷ 2; use harmonic mean 2xy ÷ (x + y)
- Average of an even set of consecutive numbers — always ends in .5
How to use this page for revision
Quiz mode: Tap any option — green = correct, red = wrong. Use the pagination buttons to move between sets of 25 MCQs at a time.
PDF download: Click Download PDF in the sticky bar to grab all 148 MCQs with answers for offline study.
Mixed practice: attempt our full PPSC Mock Test with all subjects + weighted distribution to simulate the real exam.
Average & Mean weightage by exam
| Exam | Typical Average MCQs | Marks Share |
|---|---|---|
| PPSC One Paper | 1–3 | 3–5 |
| FPSC Screening | 2–5 | 4–8 |
| NTS NAT / GAT | 3–6 | 6–10 |
| CSS Screening (MPT) | 3–6 | 6–12 |
| OTS / CTS | 2–4 | 4–7 |
| SPSC / KPPSC / BPSC | 1–3 | 3–5 |
All MCQs sourced from official past papers of PPSC, FPSC, SPSC, KPPSC and NTS. Found a wrong answer? WhatsApp 0302-1417839 — we fix every reported issue within 24 hours.
Frequently Asked Questions
Typically 1 to 3 average MCQs appear in every PPSC One Paper test (Sub-Inspector, Tehsildar, Junior Clerk, Lecturer, BPS-14/16/17). FPSC, NTS and CSS papers tend to include 2–5. Mastering this topic alone secures 3–5 guaranteed marks because the formulas are short and the patterns repeat verbatim.
Based on our analysis of 148 past-paper MCQs (2002–2025), the three most-recurring types are: (1) simple arithmetic mean of a set of numbers, (2) combined average when a third income / group is added or removed, and (3) age-related average word problems where a family member joins or leaves.
No. Calculators are not allowed in PPSC, FPSC, NTS, OTS or any provincial commission exam. Practise mental math shortcuts — 10%, 25%, 50% calculations should take under 5 seconds.
Yes for PPSC and FPSC — 0.25 marks deducted per wrong answer. Strategy: if you can eliminate 2 out of 4 options confidently, attempt it; otherwise leave blank.
Yes — click the Download PDF button in the sticky bar at the top of the quiz section. You get all 148 MCQs with answers in a branded QuizWing PDF, free, no signup.
Yes — 100% transferable. All provincial public service commissions follow a near-identical Math syllabus. The same average & mean MCQs appear (often verbatim) in SPSC, KPPSC, BPSC, AJKPSC and NTS NAT/GAT papers.
Message us on WhatsApp at 0302-1417839 with the question number and what you believe the correct answer should be. We verify against multiple sources and fix every reported issue within 24 hours.